Message-ID: <1346619265.82435.YahooMailNeo@web142601.mail.bf1.yahoo.com>
Date: 2012-09-02T20:54:25Z
From: arun
Subject: splits with 0s in middle columns
In-Reply-To: <504391C5.6080409@sapo.pt>
HI,
You can also try this as a function:
fun1<-function(x){
B<-gsub("percent{0,1}\\s\\((.*)\\)","\\1",x)
C<-gsub("(.*)/(.*)","\\1 0 0 \\2", gsub("(.*)/(.*)/(.*)","\\1 \\2 0 \\3", gsub("(.*)/(.*)/(.*)/(.*)","\\1 \\2 \\3 \\4",B)))
dat1<-data.frame(do.call(rbind,strsplit(C," ")))
colnames(dat1)<-paste0("A",1:4)
dat1
}
?fun1(A)
#? A1 A2 A3 A4
#1 10 20? 0 30
#2 40? 0? 0 20
#3 60 10 10? 5
#4 80? 0? 0 10
A.K.
----- Original Message -----
From: Rui Barradas <ruipbarradas at sapo.pt>
To: Sapana Lohani <lohani.sapana at ymail.com>
Cc: r-help <r-help at r-project.org>
Sent: Sunday, September 2, 2012 1:05 PM
Subject: Re: [R] splits with 0s in middle columns
Hello,
You don't need a new function, what you need is to prepare your data in
such a way that the function can process it.
A <- c("percent (10/20/30)", "percent (40/20)", "percent (60/10/10/5)",
"percent (80/10)")
B <- gsub("\\(|\\)|percent| ", "", A)
fun(B)
Also, please use dput to post the data examples,
dput(A)
c("percent (10/20/30)", "percent (40/20)", "percent (60/10/10/5)",
"percent (80/10)")
Then copy&paste in your post.
Rui Barradas
Em 02-09-2012 04:22, Sapana Lohani escreveu:
> Dear Rui,
>
> The new code works fine for what I wanted. I have another similar column but it looks like
>
> A
> percent (10/20/30)
> percent (40/20)
> percent (60/10/10/5)
> percent (80/10)
>
> I want a similar split but delete the percent in the front. The output should look like
>
> A1 A2 A3 A4
> 10 20 0 30
> 40 0 0 20
> 60 10 10 5
> 80 0 0 10
>
> Could you please make the small change in the code that you gave me. It must be a small edition but I could not figure that out. FYI the code that worked was
>
> fun <- function(X){
>? ? ? xname <- deparse(substitute(X))
>? ? ? s <- strsplit(X, "/")
>? ? ? n <- max(sapply(s, length))
>? ? ? tmp <- numeric(n)
>
>? ? ? f <- function(x){
>? ? ? ? ? x <- as.numeric(x)
>? ? ? ? ? m <- length(x)
>? ? ? ? ? if(m > 1){
>? ? ? ? ? ? ? tmp[n] <- x[m]
>? ? ? ? ? ? ? tmp[seq_len(m - 1)] <- x[seq_len(m - 1)]
>? ? ? ? ? }else tmp[1] <- x
>? ? ? ? ? tmp
>? ? ? }
>
>? ? ? res <- do.call(rbind, lapply(s, f))
>? ? ? colnames(res) <- paste(xname, seq_along(s), sep = "")
>? ? ? data.frame(res)
> }
>
> fun(A)
>
> Thank you so very much.
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