Parsing unusual date format

hi: i tried regular expressions and , as usual, failed. but below does do the 
job uglily using strsplit. i'd still be curious and appreciate if someone 
could do the regular expression method. thanks.

dts <- c("1990m12", "1992m8") #March 1990 and Aug 1992

#SPLIT IT USING m
temp <- strsplit(dts,"m")

# PASTE THE #'S BUT CHECK
# FOR GREATER THAN 9 UGLIFIES IT
moddates <- lapply(temp,function(.str) {
 if ( as.numeric(.str[2]) > 9 ) {
   paste(.str[1],as.numeric(.str[2]),"01",sep="-")
 } else {
   paste(.str[1],"-0",as.numeric(.str[2]),"-01",sep="")
 }
})

# MAKE  THE DATE
datelist<-lapply(moddates,as.Date ,format="%Y-%m-%d")




On Thu, Dec 18, 2008 at  1:14 AM, Shruthi Jayaram wrote:

Hello,

If I have a character string like

d <- c("1990m3", "1992m8") #March 1990 and Aug 1992

what is the easiest way to convert it into any standard date form; for
example,

d <- c("01/03/1990", "01/08/1992")
I looked at as.Date but it doesn't seem to address my problem as I have an
"m" stuck in the middle of my character string which R does not recognise.

Would be very grateful for any help on this.
Shruthi
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