Legend containing maths symbol and values of variables
that should have been:
L <- list(bquote("Up (" >= .(threshold) ~ ")"), "Normal", "Down", "NA")
legend("top", leg = as.expression(L))
On Tue, Mar 24, 2009 at 7:18 AM, Gabor Grothendieck
<ggrothendieck at gmail.com> wrote:
Try this:
L <- list(bquote("Up (" >= .(threshold) ~ ")"), "Normal", "Down", "NA")
legend("top", leg = L)
On Tue, Mar 24, 2009 at 2:52 AM, Daren Tan <darentan76 at gmail.com> wrote:
I tried sprintf and paste, which solves one of my problem i.e. replacing the variable name by its value. However, >= is not renderend correctly as the inequality symbol. On Tue, Mar 24, 2009 at 12:24 PM, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
For the legend argument try this:
leg = as.expression(c(sprintf("Up (>= %d)", threshold),
? ? ? ?"Normal", "Down", "NA"))
or use paste in place of sprintf.
On Mon, Mar 23, 2009 at 11:53 PM, Daren Tan <darentan76 at gmail.com> wrote:
I need to have the maths symbol for >= in the legend, and to
substitute threshold variable with its value. Somehow, various
attempts weren't successful. Please help.
threshold <- 0.5
plot(NA, xlab="", ylab="", main="", axes=F, xlim=c(0,1), ylim=c(0,1),
xaxs="i", yaxs="i")
legend(x=0, y=1, fill=c("orange", "white", "green", "gray90"),
cex=0.8, pt.cex=1.8, x.intersp=0.6, bg = "white",
? ? ? ? ? legend=c(expression("Up (" >= threshold ")"), "Normal",
"Down", "NA"), bty = "n")
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