lda: how to get the eigenvalues
let's compare lda and discrimin (ade4) using the iris data: with lda I get:
lda1 <- lda(iris[,1:4],iris[,5]) lda1$svd
[1] 48.642644 4.579983 with discrimin:
discrimin1 <- discrimin(dudi.pca(iris[,1:4],scan=F),iris[,5],scan=F) discrimin1
eigen values: 0.9699 0.222 so where and how is the relationship? thanks christoph
On Tue, 2003-06-03 at 13:01, Prof Brian Ripley wrote:
On Tue, 3 Jun 2003, Stephane Dray wrote:
On Tue, 3 Jun 2003, Christoph Lehmann wrote:
How can I get the eigenvalues out of an lda analysis?
It uses singular values not eigenvalues: see ?lda for a description of the output, and the print method for one way to use them.
the function discrimin ofthe ade4 package performs discriminat analysis with eigen and so produces eigenvalues ($eig)
For those for whom squaring is too difficult, that is. Why recommend software using an inferior algorithm to avoid squaring?
Christoph Lehmann <christoph.lehmann at gmx.ch>