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Rank-based p-value on large dataset

On Thursday 03 March 2005 16:22, Sean Davis wrote:
The obvious thing to do would be 

p.val = 1 - ecdf(x)(y)

wouldn't it? On a 1.1 GHz Athlon, I get
[1] 1.03 0.03 1.06 0.00 0.00

-Deepayan