dynamic lists (data frames?)
Got it thanks
the trick was to create a variable with the new name
str_idx<-paste('c',i,sep='')
then use double square brackets
l_cooef[str_idx]]<-whatever()
f_haardisolve<-function(v_dataset){
#pad data to make length a power of 2
v_dataset<-f_paddata(v_dataset)
l_cooef<-list() #holder for cooefficents
i_count<-1 #identity counter
while(length(v_dataset)>0){
#seperate odd and even points
v_dataset<-f_splitpoints(v_dataset)
v_dataset<-f_haarpredict(v_dataset)
v_dataset<-f_haaruplift(v_dataset)
str_idx<-paste('c',i_count,sep='')
l_cooef[[str_idx]]<-list()
l_cooef[[str_idx]]<-v_dataset[c((length(v_dataset)/2)+1:(length(v_dataset)/2))]
v_dataset<-v_dataset[c(1:length(v_dataset)/2)]
i_count<-i_count+1
}
l_cooef
}
On Tue, 2005-27-09 at 10:39 -0400, tom wright wrote:
Can someone please show me what I need to get something like this to
work
for(a in c(1:5)){
data$a<-c(a:10)
}
so that i end up with a structure
data$1<-[1,2,3,4,5,6,7,8,9,10]
data$2<-[2,3,4,5,67,8,9,10]
data$3<-[3,4,5,67,8,9,10]
data$4<-[4,5,67,8,9,10]
data$5<-[5,67,8,9,10]
thanks loads
Tom
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