formula argument evaluation

Would making it regular function %=>%, using "%" instead of quotes,
work for you?

On Tue, Apr 12, 2016 at 11:09 AM, Adrian Du?a <dusa.adrian at unibuc.ro>
wrote:

On Tue, Apr 12, 2016 at 2:08 PM, Duncan Murdoch <

murdoch.duncan at gmail.com>

wrote:

[...]

It never gets to evaluating it.  It is not a legal R statement, so the

parser signals an error.

If you want to pass arbitrary strings to a function, you need to put

them

in quotes.

I see. I thought it was parsed inside the function, but if it's parsed
before then quoting is the only option.


To Keith: no, I mean it like this "A + B => C" which is translated as:
"the union of A and B is sufficient for C" in set theoretic language.

The "=>" operator means sufficiency, while "<=" means necessity. Quoting
the expression is good enough, I was just curious if the quotes could be
made redundant, somehow.

Thank you both,
Adrian

--
Adrian Dusa
University of Bucharest
Romanian Social Data Archive
Soseaua Panduri nr.90
050663 Bucharest sector 5
Romania

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