Message-ID: <Pine.LNX.4.21.0005260835040.30807-100000@pc16.stat.umu.se>
Date: 2000-05-26T06:37:08Z
From: Göran Broström
Subject: Kaplan-Meier for left truncated data?
In-Reply-To: <000e01bfc6d6$49c65960$acc643c3@oemcomputer>
On Fri, 26 May 2000, Fredrik Lundgren wrote:
> R-users!
>
> How do I ask for the 'baseline hazard' of a coxph fit??
This interesting:
> start <- c(1,2,1,1)
> stopp <- c(3,4,5,6)
> event <- c(1,1,1,1)
> library(survival5)
> survfit(Surv(start, stopp, event))
Error in survfit.km(X, Y, casewt, ...) : Can only handle right censored
data
Does not work :-(
> res <- coxph(Surv(start, stopp, event) ~ 1)
> survfit(res)
Is ok! :-)
G?ran
>
> Fredrik Lundgren
> ----- Ursprungligt meddelande -----
> Fr?n: "gb" <gb at stat.umu.se>
> Till: <r-help at stat.math.ethz.ch>
> Skickat: den 25 maj 2000 21:25
> ?mne: Re: [R] Kaplan-Meier for left truncated data?
>
>
> >
> > I have got two late answers to this question, from Mai Zhou and Bendix
> > Carstensen. Both point out a 'trick': Use coxph to fit a model with
> > no covariates and ask for the 'baseline hazard' of that fit!
> > Unlike survfit, coxph allows for left truncated data.
> >
> > Thanks to both!
> >
> > G?ran
> >
> > > On Sun, 21 May 2000, gb wrote:
> > >
> > > >
> > > > Is there a function somewhere for estimating the survivor function
> > > > (plus confidence limits) when data are both left truncated and right
> > > > censored? survfit in survival5 doesn't like left truncation.
> >
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>
>
--
G?ran Brostr?m, professor tel: +46 90 786 5223
Department of Statistics fax: +46 90 786 6614
Ume? University
SE-90187 Ume?, Sweden e-mail: gb at stat.umu.se
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