test if elements of a character vector contain letters
You probably mean grepl('[a-zA-Z]', x)
Regards,
Yihui
--
Yihui Xie <xieyihui at gmail.com>
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Mon, Aug 6, 2012 at 3:29 PM, Liviu Andronic <landronimirc at gmail.com> wrote:
On Mon, Aug 6, 2012 at 6:42 PM, Bert Gunter <gunter.berton at gene.com> wrote:
nzchar(x) & !is.na(x) No?
It doesn't work for what I need:
x
[1] "a10" "b8" "c9" "d2" "e3" "f4" "g1" "h7" "i6" "j5" "k" "l" "m" "n" [15] "o" "p" "q" "r" "s" "t" "u" "v" "w" "x" "y" "z" "1" "2" [29] "3" "4" "5" "6" "7" "8" "9" "10" "11" "12" "13" "14" "15" "16" [43] "17" "18" "19" "20" "21" "22" "23" "24" "25" "26"
nzchar(x) & !is.na(x)
[1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE [18] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE [35] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE [52] TRUE I need to have TRUE when an element contains a letter, and FALSE when an element contains only numbers. The above returns TRUE for the entire vector. Regards Liviu