-----Original Message-----
From: Mike Meyer [mailto:mikem at salter-point.com]
Sent: Thursday, October 27, 2005 3:43 PM
To: Berton Gunter
Cc: r-help at stat.math.ethz.ch
Subject: Re: [R] How to manipulate an abitrary dimensioned array.
Thanks for the suggestion.
Perhaps I can see how to use apply to get the ratio, but say
I also want
to return X[,,,,1] in a general way. Maybe I am being dense
but I just
don't see it --- probably as a result of too much Perl/Python/Java
recently that is clouding my mind.
So can someone suggest a general function that will give me the last
layer of an arbitrary dimensioned array?
Berton Gunter wrote:
Why doesn't apply() already do what you want?
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
"The business of the statistician is to catalyze the
process." - George E. P. Box
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of Mike Meyer
Sent: Thursday, October 27, 2005 2:50 PM
To: r-help at stat.math.ethz.ch
Subject: [R] How to manipulate an abitrary dimensioned array.
If I have an n1 x n1 x 2 array X I can calculate, say,
X[,,1]/X[,,2].
If it is a 4 dimensional array then I want to be able to calculate
X[,,,1]/X[,,,2], and similarly for higher dimensions.
How can I write a function to do this in a general way
without having to
do a switch for each possible length(dim(X)). So I want a
that will take an arbitrary dimensioned array, X, and return
X[,,,1]/X[,,,2], etc. I know how to do this by turning X into a
vector, then doing the division, then re-shaping as an array,
but that
doesn't seem very elegant.
What I think I am missing is how to paste/substitute/eval a
commas into an array selection.
Thanks, --Mike
--
Mike Meyer, Seattle WA