extrat non diagonal

A <- matrix(1:9,3,3,

A

matrix( A[row(A)!=col(A)], nrow(A)-1, ncol(A), dimnames=list(NULL,

An even better solution because it has fewer steps.

A <- matrix(1:9, 3, 3)
A
B <- A[-1, ]
B[upper.tri(B, diag=FALSE)] <- A[upper.tri(A)]
B

A <- matrix(1:9, 3, 3)
A

     [,1] [,2] [,3]
[1,]    1    4    7
[2,]    2    5    8
[3,]    3    6    9

B <- A[-1, ]
B[upper.tri(B, diag=FALSE)] <- A[upper.tri(A)]
B

     [,1] [,2] [,3]
[1,]    2    4    7
[2,]    3    6    8

On Wed, Nov 14, 2018 at 2:09 PM Richard M. Heiberger <rmh at temple.edu>
wrote:

Steve's method is very slick.

I think this is a bit easier to understand.

A <- matrix(1:9, 3, 3)
A
B <- matrix(nrow=2, ncol=3)
B[lower.tri(B, diag=TRUE)] <- A[lower.tri(A)]
B[upper.tri(B, diag=FALSE)] <- A[upper.tri(A)]
B

A <- matrix(1:9, 3, 3)
A

     [,1] [,2] [,3]
[1,]    1    4    7
[2,]    2    5    8
[3,]    3    6    9

B <- matrix(nrow=2, ncol=3)
B[lower.tri(B, diag=TRUE)] <- A[lower.tri(A)]
B[upper.tri(B, diag=FALSE)] <- A[upper.tri(A)]
B

     [,1] [,2] [,3]
[1,]    2    4    7
[2,]    3    6    8

On Wed, Nov 14, 2018 at 11:04 AM S Ellison <S.Ellison at lgcgroup.com>

wrote:

i) Your code creates w2 but references w1 to create aa.

So you needed
aa <- matrix(rep(c(0.4, 0.1, 0.2), 3), 3,3)
for a working example.

ii) This

matrix(as.numeric(aa)[!as.numeric(aa) %in% diag(aa)],2,3)

removes any value that is present in the diagonal of aa. Look up

?"%in%" to see what that does; it returns TRUE whenever anything in
as.numeric(aa) matches anything in your diagonal. All the values in aa
match one of c(0.4, 0.1, 0.2). So since your whole matrix consists of these
three numbers, you told R to leave out everything in aa and then create a
2x3 matrix with the result. Hence the NAs

iii) If you want to extract odd parts of a matrix explicitly, see ?"["

and particularly the section on indexing using arrays

iv) You can use logical indexing. In the special case of the diagonal,

you can use diag() to create a matrix of logicals, logically negate that
and apply that to your matrix:

aa[ !diag(rep(TRUE, 3)) ]

and, in twoi rows:
matrix( aa[ !diag(rep(TRUE, 3)) ], 2,3)

for examplei have this matrix
w2<-c(0.1,0.2,0.4,0.2,0.4,0.1)
aa<-matrix(w1,nrow=3,ncol=3)
aa
     [,1] [,2] [,3]
[1,]  0.4  0.4  0.4
[2,]  0.1  0.1  0.1
[3,]  0.2  0.2  0.2

if i use this code
matrix(as.numeric(aa)[!as.numeric(aa) %in% diag(aa)],2,3)

i will obtaine this matrix[,1] [,2] [,3]
[1,]   NA   NA   NA
[2,]   NA   NA   NA

but me i want this matrix[,1] [,2] [,3]
[1,]  0.1  0.4  0.4
[2,]  0.2  0.2  0.1

thank you

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