replacing with NA

x[is.na(z)] <- NA

This might send you a nasty bug if x and z are different lengths
though -- just a head's up.

Michael

On Wed, May 16, 2012 at 12:55 PM, Mintewab Bezabih
<Mintewab.Bezabih at economics.gu.se> wrote:

Dear R users,

I was wondering  how I can replace the values of a vector with the 

values from in another vector in the same row

For example, how can I replace the value of x below with NA when the 

value of Z in the same row is NA?

x <-1:20
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, 

Many thanks
Mintewab

am able to run my codes alright but I want the non missing values to be 
correctly identified and therefore want to tag my id vector along in my 
results. Since the vector of ids has no role in the analysis, I dont 

how to include it.

Here is my reprducable example:and my id is the vector I want to add 

the analysis somehow so that my missing values are identified. I cannot 
use  na.action function and that is why I have to drop my missing 
obesevations beforehand.

library(fields)
x <-1:20
y<- runif(20)
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,
17, NA, 12, 10)
id <-1:20

mydataset<-data.frame(x, y, z)
temperature[complete.cases(mydataset),]

 x<- temperature[, c(1)]
y<- temperature[, c(2)]
z<- temperature[, c(3)]

tpsfit <- Tps(cbind(x, y), z, scale.type="unscaled")




Many thanks as always.
Regards,
Mintewab