understanding lexical scope
Wacek Kusnierczyk wrote:
Peter Dalgaard wrote:
One distinction is if you have things like #define f(x) 2*x #define g(y) f(y+2) (in the C language preprocessor syntax), then you end up with g(y) as y+2*2 (i.e., y+4), whereas the corresponding function calls give 2*(y+2). Also, and the flip side of the original question: Macros have difficulties with encapsulation; with a bit of bad luck, arguments given to f() can modify its internal variables.
using c macros, you end up with g(y) substituted by 2*y+2, rather than y+2*2, as you say (and rather than 2*(y+2), which you'd effectively get using a function).
Oops. Yes. I suppose I had x*2 there at some point....
that's why you'd typically include all occurences of all macro 'parameters' in the macro 'body' in parentheses: #define f(x) 2*(x) some consider using c macros as not-so-good practice and favour inline functions. but macros are not always bad; in scheme, for example, you have a hygienic macro system which let's you use the benefits of macros while avoiding some of the risks. vQ
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