From vector to a step function
Dear Jim Holtman, I would like to thank you for your help. Just to update also the community that worked fine :) Best Regards Alex
--- On Mon, 1/10/11, jim holtman <jholtman at gmail.com> wrote:
From: jim holtman <jholtman at gmail.com> Subject: Re: [R] From vector to a step function To: "Alaios" <alaios at yahoo.com> Cc: r-help at r-project.org Date: Monday, January 10, 2011, 5:44 PM try this:
f.main <- function(vec){
+? ???breaks <- seq(-3, by = 1,
length = length(vec) + 1L)
+? ???function(x){
+? ? ? ???indx <-
findInterval(x, breaks)
+? ? ? ???vec[indx]
+? ???}
+ }
f1 <- f.main(c(3,4,5,1,2,3,4,5)) f2 <- f.main(c(5,6,2,4,7,3,2,5)) f3 <- f.main(c(1,2,4,7,3,1,3,5)) f1(c(-2.5,-2,-.5,0,.5,1.5,2.5))
[1] 3 4 5 1 1 2 3
f2(c(-2.5,-2,-.5,0,.5,1.5,2.5))
[1] 5 6 2 4 4 7 3
f3(c(-2.5,-2,-.5,0,.5,1.5,2.5))
[1] 1 2 4 7 7 3 1
On Mon, Jan 10, 2011 at 11:42 AM, Alaios <alaios at yahoo.com> wrote:
Greetings R members. I have a few vectors that denote the 'steps' of
different step functions
v1=c(3,4,5,1,2,3,4,5) v2=c(5,6,2,4,7,3,2,5) v3=c(1,2,4,7,3,1,3,5) Here v1,v2,v3 are considered as the steps for the
f1,f2,f3 step functions.
For example f1 looks like that (step size is always
same and fixed)
f1= 3 (x>=-3,x<-2) f1= 4 (x>=-2,x<-1) f1= 5 (x>=-1,x<0) f1= 1 (x>=0, x<1) and so on. What I only have are these vectors that are
interpreted as functions (as shown above, x (step is 1 here). I would like to ask your help of how I can create some function that reads one of the vector v1,v2,v3.... and returns results that are acceptable by integrate() function.
Usually integrate wants a pre-defined function like
myfunc(x)<-function{ x^2 }
but this is not the case here.
Could you please give me some hints how I can
proceed?
I would like to thank u in advance for your help Regards Alex
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