Is there a simple way to analyse all the data using dplyr?

I am sure the answer is "yes" and I'm also sure the question may sound mad. Here's a reprex that I think captures what I'm doing

n <- 500
gender <- sample(c("Man","Woman","Other"), n, replace = TRUE)
GPC_score <- rnorm(n)
scaleMeasures <- runif(n)
bind_cols(gender = gender,
GPC_score = GPC_score,
scaleMeasures = scaleMeasures) -> tibUse

### let's have the correlation between the two variables broken down by gender
tibUse %>%
  filter(gender != "Other") %>%
  select(gender, GPC_score, scaleMeasures) %>%
  na.omit() %>%
  group_by(gender) %>%
  summarise(cor = cor(cur_data())[1,2]) -> tmp1

### but I'd also like the correlation for the whole dataset, not by gender
### this is a kludge to achieve that which I am using partly because I cant'
### find the equivalent of cur_data() for an ungrouped tibble/df
tibUse %>%
  mutate(gender = "All") %>% # nasty kludge to get all the data!
  select(gender, GPC_score, scaleMeasures) %>%
  na.omit() %>%
  group_by(gender) %>% # ditto!
  summarise(cor = cor(cur_data())[1,2]) -> tmp2

bind_rows(tmp1,
  tmp2)

### gets me what I want:
# A tibble: 3 x 2
gender cor
<chr> <dbl>
1 Man 0.0225
2 Woman 0.0685
3 All 0.0444

In reality I have some functions that are more complex than cor()[2,1] (sorry about that particular kludge) that digest dataframes and I'd love to have a simpler way of doing this.

So two questions:
1) I am sure there a term/function that works on an ungrouped tibble in dplyr as cur_data() does for a grouped tibble ... but I can't find it.
2) I suspect someone has automated a way to get the analysis of the complete data after the analyses of the groups within a single dplyr run ... it seems an obvious and common use case, but I can't find that either.

Sorry, I'm over 99% sure I'm being stupid and missing the obvious here ... but that's the recurrent problem I have with my wetware and searchware doesn't seem to being fixing this!

TIA,

Chris

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Chris Evans <chris at psyctc.org> Visiting Professor, University of Sheffield <chris.evans at sheffield.ac.uk>
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