Message-ID: <CAAmySGNsBZ3nkdCu32+LUDdf+iA0Eo0ttwxj7nY9PmgKSi11Jw@mail.gmail.com>
Date: 2012-09-18T14:58:31Z
From: R. Michael Weylandt
Subject: extracting column and regular interval in R
In-Reply-To: <BLU150-W32CDB75E6FAEE468C10F3289940@phx.gbl>
x[c(TRUE, rep(FALSE, 36)),]
and let recycling work its magic!
To concretize:
x <- 1:100
x[c(TRUE, rep(FALSE, 4))]
Cheers,
Michael
On Tue, Sep 18, 2012 at 3:55 PM, eliza botto <eliza_botto at hotmail.com> wrote:
>
> Dear R users,
> i have a matrix with 31 rows and 444 columns and i want to extract every 37th column of that matrix starting from 1. more precisely i want to select columns 1, 38,75, 112 and so on. then doing the same by starting from column number 2(2,39,76,113.......).
> i know that there is a manual way of doing it but i wanted to make it more quickly as i have fairly large data to dealth with.
>
> thanks in advance
> eliza
> [[alternative HTML version deleted]]
>
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