lazy evaluation question

Gabor Grothendieck wrote:

Note that

rm(i)
for(j in 1:4) F(j)

raises an error due to scoping issues.

Yes. This has nothing to do with lazy evaluation, and everything to do with
scoping: f is not defined in the scope of F, so does not know about its
variables (nor those in the implicit loop of lapply()).

Notice also that in

lapply(1:4,function(i) F(i))

it would be pretty weird if lapply would behave differently depending on the
name of formal arguments of the function, i.e. if

lapply(1:4,function(meep) F(meep))

gave a different result. And f() depends on looking for a variable i outside
of the function.