a little probleme
On Wed, Jul 04, 2001 at 01:49:50PM +0200, Olivier Martin wrote:
i would like to find the best way to resolve the following problem. Suppoose i have a vector x of length N with k different elements. length(x)=N u<-unique(x) length(u)=k I would like to get a matrix M with k rows and N columns such that: in each line i (i=1,...,k), which(x%in%u[i]) is equal to 1 and 0 else.
You can try something along the lines of the following
small function (sort, colnames and rownames stuff are optional)
try.me <- function(a)
{
n <- length(a)
u <- sort(unique(a))
m <- length(u)
ans <- matrix(0,n,m)
ans[rep(u,rep(n,m))==a] <- 1
colnames(ans) <- u
rownames(ans) <- a
ans
}
Example:
a <- rbinom(10,3,0.5) a
[1] 1 3 2 2 1 2 0 3 1 3
try.me(a)
0 1 2 3 1 0 1 0 0 3 0 0 0 1 2 0 0 1 0 2 0 0 1 0 1 0 1 0 0 2 0 0 1 0 0 1 0 0 0 3 0 0 0 1 1 0 1 0 0 3 0 0 0 1
a<-c("Chopin","Mozart","Mozart","Debussy")
try.me(a)
Chopin Debussy Mozart Chopin 1 0 0 Mozart 0 0 1 Mozart 0 0 1 Debussy 0 1 0 or make use of the built-in model.matrix function which is essentially equivalent to what you ask:
model.matrix(~as.factor(a)-1)
as.factor(a)Chopin as.factor(a)Debussy as.factor(a)Mozart 1 1 0 0 2 0 0 1 3 0 0 1 4 0 1 0 attr(,"assign") [1] 1 1 1 guido -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._