Message-ID: <1F2CE8D4B0195E488213E8B8CCF71486025012E2@saffron.cfs.le.ac.uk>
Date: 2003-07-25T10:44:15Z
From: Hotz, T.
Subject: variable name of variable in dataframe
Dear Tobias,
The trick is "Programming on the Language", see e.g. the "R Language Manual".
Construct the expression you want, and have it explicitly parsed and evaluated.
toy <- function(b=.95){
toyframe <- eval(parse(text=paste("data.frame(lion", b, " = c(1, 2))", sep="")))
return(toyframe)
z}
toy()
toy(0)
HTH
Thomas
---
Thomas Hotz
Research Associate in Medical Statistics
University of Leicester
United Kingdom
Department of Epidemiology and Public Health
22-28 Princess Road West
Leicester
LE1 6TP
Tel +44 116 252-5410
Fax +44 116 252-5423
Division of Medicine for the Elderly
Department of Medicine
The Glenfield Hospital
Leicester
LE3 9QP
Tel +44 116 256-3643
Fax +44 116 232-2976
> -----Original Message-----
> From: Tobias Verbeke [mailto:tobias_verbeke at skynet.be]
> Sent: 25 July 2003 11:16
> To: R-help
> Subject: [R] variable name of variable in dataframe
>
>
> Dear list,
>
> If I have this toy function:
>
> toy <- function(b=.95){
> toyframe <- data.frame(lion.95 = c(1, 2))
> return(toyframe)
> }
>
> How can I obtain that for any value b,
> the name of the column becomes "lionb",
> i.e. lion.95 if b = .95, lion.85 if b = .85 etc.
> knowing that .95 (.85 etc.) may also be
> given as 0.95 (0.85 etc.) but that the
> result should be lion.95 (lion.85 etc.)
>
>
> Thanks in advance,
>
> Tobias
>
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