Thank you for that Pascal.
I changed this bit to the following:
result <- vector("list", (length(test1)-1))
for(i in 1:(length(test1)-1))
{
for(j in i+1:length(test1))
{
result[[i]][j-i] <- agrep(test1[i], test1[j], ignore.case = TRUE,
value = TRUE, max.distance = 0.1)
}
}
And now I get the error - Error in result[[i]][j - i] <- agrep(test1[i],
test1[j], ignore.case = TRUE, :
replacement has length zero
What does this mean?
On Tue, Dec 11, 2012 at 1:24 PM, Pascal Oettli <kridox at ymail.com
<mailto:kridox at ymail.com>> wrote:
Hi,
There is a mistake in the first line. It should be:
> for(i in 1:(length(test1)-1))
Regards,
Pascal
Le 11/12/2012 16:01, surekha nagabhushan a ?crit :
Hi all.
This is my first message at R-help...so I'm hoping I have some
beginner's
luck and get some good help for my problem!
FYI I have just started using R recently so my knowledge of R is
pretty
preliminary.
Okay here is what I need help with - I need to know how to use
agrep in a
for loop.
I need to compare elements of a vector of names with other
elements of the
same vector.
However if I use something like this:
for(i in 1:length(test1)-1)
{
for(j in i+1:length(test1))
{
result[[i]][j] <- agrep(test1[i], test1[j], ignore.case =
TRUE, value =
TRUE, max.distance = 0.1)
}
}
I get an error message saying - invalid 'pattern' argument. -*
Error in
agrep(test1[i], test1[j], ignore.case = TRUE, value = TRUE,
max.distance =
0.1) : *
* invalid 'pattern' argument*
Test 1 being - c("Vashi", "Vashi,navi Mumbai", "Thane",
"Vashi,new Mumbai",
"Thana", "Surekha", "Thane(w)", "surekhaN")
This is the first time I'm using agrep, I do not understand how
it works
fully...
Kindly help...
Thank you.
Su.
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