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Aggregating by a grouping

One possibility is:
[1] "A" "B" "C" "D" "A" "C" "D" "B"
[1] 10 11  9  8 12  4  5  7
[[1]]
[1] "A" "B"

[[2]]
[1] "C" "D"
u),arr.ind=TRUE)
Group.1  x
1       1 40
2       2 26
--- "Kondamani, Arjun (GMI - NY Corporate Bonds)"
<arjun_kondamani at ml.com> wrote:

            
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