thanks stephan. i'd been trying to make gsub work, but couldnt make it
replace the whole expression. so i'd resorted to trying to loop with grep -
but with two problems. firstly, i cant seem to make the loop 'remember'
the substitutions it makes (see below). secondly, it feels like this is a
really inefficient way of doing something quite simple anyhow.
colours <- as.character(paste(letters,colours(),"stuff",LETTERS))
target <- c("red","blue","green","gray")
new.colour <-colours
for (i in length(target)) {
x <- target[i]
new.colour[grep((x),new.colour)] <- x
return(new.colour)
}
On Sat, Mar 28, 2009 at 9:45 AM, Stephan Kolassa <Stephan.Kolassa at gmx.de>wrote:
Hi Simeon,
?gsub
HTH,
Stephan
simeon duckworth schrieb:
I am trying to simplify a text variable by matching and replacing it with
a
string in another vector
so for example in
colours <- paste(letters,colours(),"stuff",LETTERS)
find and replace with ("red","blue","green","gray","yellow","other") -
irrespective of case
its a large dataset, so i'd like to be able to do this as efficiently as
possible.
thanks for any help
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