Dear Sohail,
Using Jim's data set skdat, two more options would be
# first option
d <- with(skdat, table(ID, lettertag))
names <- colnames(d)
d <- c(list(rownames(d)), lapply(1:ncol(d), function(i) as.numeric(d[,i])))
names(d) <- c('ID', names)
d
# second option
d <- with(skdat, table(ID, lettertag))
res <- c(list(rownames(d)), sapply(apply(d, 2, list), "[", 1))
names(res)[1] <- "ID"
res
HTH,
Jorge.-
On Fri, Aug 15, 2014 at 7:19 PM, Jim Lemon <jim at bitwrit.com.au> wrote:
On Thu, 14 Aug 2014 06:08:51 PM Sohail Khan wrote:
Hi
I have data set as follows:
A 92315 A 35018 A 56710 B 52700 B 92315 B 15135 C 35018 C
I would like to transform this data set into:
ID 92315 35018 56710 52700 15135 A 1 1 1 0 0 B 1 0 0 1 1 C 0 1 0
I looked into reshape package to no avail.
I would appreciate any suggestions.
-Sohail
Hi Sohail,
You are doing a bit more than reshaping. This may get you there:
skdat<-read.table(text="A 92315
A 35018
A 56710
B 52700
B 92315
B 15135
C 35018
C 52700",stringsAsFactors=FALSE)
names(skdat)<-c("lettertag","ID")
ID<-unique(skdat$ID)
lettertags<-unique(skdat$lettertag)
newskdat<-list(ID)
for(i in 1:length(lettertags))
newskdat[[i+1]]<-
as.numeric(ID %in% skdat$ID[skdat$lettertag==lettertags[i]])
names(newskdat)<-c("ID",lettertags)
I'm assuming that you don't really want your answer as a single string.
Jim