evaluating expressions with sub expressions
Folks: Stripped to its essentials, Jennifer's request seemed simple: substitute a subexpression as a named variable for a variable name in an expression, also expressed as a named variable. A simple example is:
e <- expression(0,a*b) z1 <- quote(1/t) ## explained below
The task is to "substitute" the expression in z1, "1/t", for "b" in e, yielding the substituted expression as the result. Gabor provided a solution, but it seemed to me like trying to swat a fly with a baseball bat -- a lot of machinery for what should be a more straightforward task. Of course, just because I think it **should be** straightforward does not mean it actually is. But I fooled around a bit (guided by Gabor's approach and an old Programmer's Niche column of Bill Venables) and came up with:
f <- lapply(e,function(x){do.call(substitute,list(x,list(b=z1)))})
f
[[1]] [1] 0 [[2]] a * (1/t)
## f is a list. Turn it back into an expression f <- as.expression(f) ## check that this works as intended f
expression(0, a * (1/t))
a <- 2 t <- 3 eval(f)
[1] 0.6666667 Now you'll note that to do this I explicitly used quote() to produce the variable holding the subexpression to be substituted. You may ask, why not use expression() instead, as in
z2 <- expression(1/t)
This doesn't work:
f <- lapply(e,function(x){do.call(substitute,list(x,list(b=z2)))})
f
[[1]] [1] 0 [[2]] a * expression(1/t)
f <- as.expression(f)
## Yielding ...
f
expression(0, a * expression(1/t)) #### Not what we want! ## And sure enough ...
eval(f)
Error in a * expression(1/t) : non-numeric argument to binary operator I think I understand why the z <- expression() approach does not work; but I do not understand why the z <- quote() approach does! The mode of the return from both of these is "call", but they are different (because identical() tells me so). Could someone perhaps elaborate on this a bit more? And is there a yet simpler and more straightforward way to do the above than what I proposed? Cheers, Bert Gunter Genentech Nonclinical Statistics -----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Gabor Grothendieck Sent: Friday, January 29, 2010 11:01 AM To: Jennifer Young Cc: r-help at r-project.org Subject: Re: [R] evaluating expressions with sub expressions The following recursively walks the expression tree. The esub function is from this page (you may wish to read that entire thread): http://tolstoy.newcastle.edu.au/R/help/04/03/1245.html esub <- function(expr, sublist) do.call("substitute", list(expr, sublist)) proc <- function(e, env = parent.frame()) { for(nm in all.vars(e)) { if (exists(nm, env) && is.language(g <- get(nm, env))) { if (is.expression(g)) g <- g[[1]] g <- Recall(g, env) L <- list(g) names(L) <- nm e <- esub(e, L) } } e } mat <- expression(0, f1*s1*g1) g1 <- expression(1/Tm) vals <- data.frame(f1=1, s1=.5, Tm=2) e <- sapply(mat, proc) sapply(e, eval, vals) The last line should give:
sapply(e, eval, vals)
[1] 0.00 0.25 On Fri, Jan 29, 2010 at 11:51 AM, Jennifer Young
<Jennifer.Young at math.mcmaster.ca> wrote:
Hallo I'm having trouble figuring out how to evaluate an expression when one of the variables in the expression is defined separately as a sub expression. Here's a simplified example mat <- expression(0, f1*s1*g1) ?# vector of formulae g1 <- expression(1/Tm) ? ? ? ? ?# expansion of the definition of g1 vals <- data.frame(f1=1, s1=.5, Tm=2) # one set of possible values for variables before adding this sub expression I was using the following to evaluate
"mat"
sapply(mat, eval, vals) Obviously I could manually substitute in 1/Tm for each g1 in the definition of "mat", but the actual expression vector is much longer, and the sub expression more complicated. Also, the subexpression is often adjusted for different scenarios. ?Is there a simple way of changing this or redefining "mat" so that I can define "g1" like a macro to be used in the expression vector. Thanks! Jennifer
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.