how to turn column into column names and fill it with values
oh it seems that I can just use your last line of code and solve my problem: m2=tapply(mc$IID, list(FID=mc$FID, PLATE=mc$PLATE), mean) m2=as.data.frame(m2) library(data.table) m3=setDT(m2, keep.rownames = TRUE)[] colnames(m3)[1] <- "FID" mt=merge(mc,m3,by="FID" for(i in 4:ncol(mt)) mt[,i] <- 1 + (names(mt)[i]== mt$PLATE) Thanks!
On Tue, Sep 29, 2020 at 12:08 PM Ana Marija <sokovic.anamarija at gmail.com> wrote:
HI Bert, thank you for getting back to me. I tried this:
dat <- cbind(mc, matrix(0,ncol = 34)) head(dat)
FID IID PLATE 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 1 fam0110 G110 4RWG569 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 fam0113 G113 cherry 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 fam0114 G114 cherry 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 4 fam0117 G117 4RWG569 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 fam0118 G118 5XAV049 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 6 fam0119 G119 cherry 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 23 24 25 26 27 28 29 30 31 32 33 34 1 0 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 0 0 0 0 0 6 0 0 0 0 0 0 0 0 0 0 0 0
names(dat) <- c(names(dat)[1:34], unique(dat$PLATE))
Error in names(dat) <- c(names(dat)[1:34], unique(dat$PLATE)) : 'names' attribute [68] must be the same length as the vector [37] so names should include FID,IID,PLATE plus unique dat$PLATE how do I fix that so the code works? Also I tried a bit on my own:
head(mc)
FID IID PLATE 1 fam0110 G110 4RWG569 2 fam0113 G113 cherry 3 fam0114 G114 cherry 4 fam0117 G117 4RWG569 5 fam0118 G118 5XAV049 6 fam0119 G119 cherry ... m2=tapply(mc$IID, list(FID=mc$FID, PLATE=mc$PLATE), mean) m2=as.data.frame(m2) library(data.table) m3=setDT(m2, keep.rownames = TRUE)[] colnames(m3)[1] <- "FID" mt=merge(mc,m3,by="FID")
head(mt)
FID IID PLATE 0VXC556 1CNF297 1CWO500 1DXJ626 1LTX827 1SHK635 1TNP840 1 fam0110 G110 4RWG569 NA NA NA NA NA NA NA 2 fam0113 G113 cherry NA NA NA NA NA NA NA 3 fam0114 G114 cherry NA NA NA NA NA NA NA 4 fam0117 G117 4RWG569 NA NA NA NA NA NA NA 5 fam0118 G118 5XAV049 NA NA NA NA NA NA NA 6 fam0119 G119 cherry NA NA NA NA NA NA NA 1URP242 2BKX529 2PAG415 3DEF425 3ECO791 3FQM386 3KYJ479 3XHK903 4RWG569 1 NA NA NA NA NA NA NA NA NA 2 NA NA NA NA NA NA NA NA NA 3 NA NA NA NA NA NA NA NA NA 4 NA NA NA NA NA NA NA NA NA 5 NA NA NA NA NA NA NA NA NA 6 NA NA NA NA NA NA NA NA NA ... so this gives me the correct columns. Now is the question of how to replace NA with 2 id column name matches the rownname in PLATE column with 2 otherwise it is 1. Cheers, Ana On Tue, Sep 29, 2020 at 11:46 AM Bert Gunter <bgunter.4567 at gmail.com> wrote:
I am not sure reshape2 is appropriate for this task, but, assuming I understand correctly, it's quite easy without it. The following is one way, which probably can be done more elegantly and efficiently, but I think it does what you want.
"dat" is your example data frame, in which the columns were read in with "stringsAsFactors" = FALSE (this is important!)
dat <- cbind(dat, matrix(0,ncol = 3)) ## change 3 to 34 for your full data
names(dat) <- c(names(dat)[1:3], unique(dat$PLATE))
for(i in 4:ncol(dat)) dat[,i] <- 1 + (names(dat)[i]== dat$PLATE)
dat
Result:
FID IID PLATE 4RWG569 cherry 5XAV049
1 fam0110 G110 4RWG569 2 1 1
2 fam0113 G113 cherry 1 2 1
3 fam0114 G114 cherry 1 2 1
4 fam0117 G117 4RWG569 2 1 1
5 fam0118 G118 5XAV049 1 1 2
6 fam0119 G119 cherry 1 2 1
Bert Gunter
"The trouble with having an open mind is that people keep coming along and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Tue, Sep 29, 2020 at 9:19 AM Ana Marija <sokovic.anamarija at gmail.com> wrote:
Hello, I have a data frame like this:
head(mc)
FID IID PLATE 1 fam0110 G110 4RWG569 2 fam0113 G113 cherry 3 fam0114 G114 cherry 4 fam0117 G117 4RWG569 5 fam0118 G118 5XAV049 6 fam0119 G119 cherry ...
dim(mc)
[1] 1625 4
length(unique(mc$PLATE))
[1] 34
I am trying to make a new data frame which would look like this:
FID IID PLATE 4RWG569 cherry 5XAV049 ...
1 fam0110 G110 4RWG569 2 1 1
2 fam0113 G113 cherry 1 2 1
3 fam0114 G114 cherry 1 2 1
4 fam0117 G117 4RWG569 2 1 1
5 fam0118 G118 5XAV049 2 1 1
6 fam0119 G119 cherry 1 2 1
...
so the new data frame would have an additional 34 columns (for every
unique mc$PLATE) and if in the row of PLATE column the value is ==to
that column name I would have 2 otherwise 1
I tried to do this with:
library(reshape2)
m2=dcast(mc, IID ~ PLATE)
Using PLATE as value column: use value.var to override. Please advise, Ana
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.