Step function
On Wed, 29 Nov 2000, Matt Pocernich wrote:
I am having problem using the step function for a linear regression model. I've created an initial model containing only the intercept. Then using the step function, I've selected three variables to be considered for the model.
x0.lm<- lm(MEDV~1, data = x) anova(x0.lm)
Analysis of Variance Table
Response: MEDV
Df Sum Sq Mean Sq F value Pr(>F)
Residuals 505 42716 85
step(x0.lm, ~ CRIM + ZN + RM)
Start: AIC= 2246.51 MEDV ~ 1 Error in eval(expr, envir, enclos) : Object "MEDV" not found
I am not clear as to why the MEDV object ( the variable I am trying to predict) is not found. I receive an identical message using the command > step(x0.lm).
This is a bug, I think. The problem is that the data frame is called x. If it were called something else there wouldn't be a problem, so the workaround is to change the name of your data frame. Looking at traceback() the problem is that the data frame `x' is being searched for in the environment of add1.lm by model.frame.lm(). In most cases it doesn't find it there and goes back to the global environment, but if the data frame is called `x' (or one of 17 other things) it finds the wrong thing in environment(add1.lm). In R1.1.1 I'm not sure what can be done about this -- model.frame.lm doesn't know where to find `x' and there isn't a general solution. In R1.2 we have more information and should be able to look in environment(formula(lmobject)), but we aren't doing that yet. -thomas Thomas Lumley Assistant Professor, Biostatistics University of Washington, Seattle -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._