help with apply, please

[...snip...]
Although the above is not wrong I should have removed the rbind
which is no longer needed and simplifying it further, as it seems
that lp will do the rep for you itself for certain arguments, gives:

lp("min", rep(1,3), t(mtrx), ">=", 1)$solution  # 1 0 1

Thank you Gabor, this solution is superbe (you never stop amazing me :)
Now... it only finds _one_ of the multiple minimum solutions. In the toy 
example, there are two minimum solutions, hence I reckon the output should 
have been a list with:
[[1]]
[1] 1 0 1

[[2]]
[1] 0 1 1

Also, thanks to Duncan and yes, I do very much care finding the smallest 
possible solutions (if I correctly understand your question).

It seems that lp function is very promising, but can I use it to find _all_ 
minimum solutions?

Adrian

Adrian DUSA
Arhiva Romana de Date Sociale
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