another basic ?
On Mon, 25 Feb 2002, jimi adams wrote:
i am sure that there is a simple solution that i am just overlooking, but there is no logical test for = there is one for != and >,<, >=, <=... what do i do if i need to check if something IS EQUAL
Depends. To test if two objects are the same, you can use identical(). Or you might use == in other situations. It's hard to know without more details.
or is there an easy way, in working with a matrix of size n x 3, to sort the matrix by one of the columns?
If m is an n x 3 matrix, to sort by column 1, you could do:
m.sorted <- m[order(m[,1]), ]
-roger _______________________________ UCLA Department of Statistics rpeng at stat.ucla.edu http://www.stat.ucla.edu/~rpeng
specifically what i am trying to do is i have a matrix with individual and
group labels that is randomly generated, and is by default sorted by the
individual labels ( column 1) and i want them to be organized into unique
group labels (comlumn 2)
thanks
jimi
jimi adams
Department of Sociology
The Ohio State University
300 Bricker Hall
190 N. Oval Mall
Columbus, OH 43210-1353
614-688-4261
our mind has a remarkable ability to think of contents as being independent
of the act of thinking
-georg simmel
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html
Send "info", "help", or "[un]subscribe"
(in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch
_._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._