Compiling date
On Mon, 8 Sep 2008, Megh Dal wrote:
Hi, I have following kind of dataset (all are dates) in my Excel sheet. 09/08/08 09/05/08 09/04/08 09/02/08 09/01/08 29/08/2008 28/08/2008 27/08/2008 26/08/2008 25/08/2008 22/08/2008 21/08/2008 20/08/2008 18/08/2008 14/08/2008 13/08/2008 08/12/08 08/11/08 08/08/08 08/07/08 However I want to use R to compile those data to make all dates in same format. Can anyone please tell me any automated way for doing that?
Well you have to read them in as character first. Then use sub to make the two digit years into four digits. The following could probably be improved by a regular expression whiz, but works:
strngs <- c("06/05/08","23/11/2008")
sub("([0-9][0-9]/[0-9][0-9]/)([0-9][0-9]$)","\\120\\2",strngs)
[1] "06/05/2008" "23/11/2008" David Scott _________________________________________________________________ David Scott Department of Statistics, Tamaki Campus The University of Auckland, PB 92019 Auckland 1142, NEW ZEALAND Phone: +64 9 373 7599 ext 86830 Fax: +64 9 373 7000 Email: d.scott at auckland.ac.nz Graduate Officer, Department of Statistics Director of Consulting, Department of Statistics