filling values in a vector using smaller vector
Milton Huang wrote:
Thank you both for such beautiful solutions. Just what I was looking for! I love the Internet, R, and the R-list! There is so much opportunity to learn. In fact, looking at the replace function, I see the two solutions are the same:
replace
function (x, list, values)
{
x[list] <- values
x
}
<environment: namespace:base>
not exactly. an application of replace generates a local copy of the data, and whatever you pass to replace as x will not be modified, while if you do the assignment yourself, you'll modify the data.
Thanks again. You made my day. Have a happy holiday season.
you too! meRRy chRistmas and a happy new yeaR to all subscRibeRs. vQ