how to setdiff on lists of lists
You can also try 'mapply'
aa<-list(c(1:3), c(4:6)) bb<-list(3,5) mapply(setdiff, aa, bb)
[,1] [,2] [1,] 1 4 [2,] 2 6
On Fri, Feb 1, 2013 at 5:16 AM, Simone Gabbriellini
<simone.gabbriellini at gmail.com> wrote:
Dear List, I have a data structure like:
aa
[[1]] [1] 1 2 3 [[2]] [1] 4 5 6
bb
[[1]] [1] 3 [[2]] [1] 5 I would like to set differences between "aa" and "bb" and get as result another list of lists like:
res
[[1]] [1] 1 2 [[2]] [1] 4 6 I am trying: lapply(aa, setdiff, bb) but I simply get "aa" back as result. Could you please point me in the right direction about the combination of functions that I need to accomplish this task? Best regards, Simone -- Simone Gabbriellini, PhD PostDoc at DISI, University of Bologna mobile: +39 340 39 75 626 email: simone.gabbriellini at unibo.it home: www.digitaldust.it DigitalBrains srl Amministratore mobile: +39 340 39 75 626 email: simone.gabbriellini at digitalbrains.it home: www.digitalbrains.it
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