Computing growth rate
Dear Mr. Barradas, Thanks a lot for pointing that. I tried that in a few steps- 1. when I evaluated d<-ddply(df1,"co_code1",transform, growth <- ifelse(diff(fyear1)==1, (exp(diff(log(df1$sales1)))-1)*100, NA)) I got the following, i.e., I was not getting the growth column automatically. co_code1 fyear1 sales1 1 1100 1990 1000 2 1100 1991 1100 3 1100 1992 1200 4 1100 1993 1300 5 1100 1995 1500 6 1100 1996 1600 7 1200 1991 1100 8 1200 1992 1200 9 1200 1993 1300 10 1200 1994 1400 11 1200 1995 1500 12 1200 1996 1600 13 1300 1990 1000 14 1300 1992 1200 15 1300 1993 1300 16 1300 1994 1400 17 1300 1995 1500 18 1300 1996 1600 2. When, just for the heck of it, the assign mark (<-) was changed to '=' as done previously, d<-ddply(df1,"co_code1",transform, growth = ifelse(diff(fyear1)==1, (exp(diff(log(df1$sales1)))-1)*100, NA)) It was no longer evaluated-error was "Error in data.frame(list(co_code1 = c(1100, 1100, 1100, 1100, 1100, 1100 : arguments imply differing number of rows: 6, 5" 3. The following gives the desired result df1$growth<-c(NA, ifelse(diff(df1$fyear1)==1, (exp(diff(log(df1$sales1)))-1)*100, NA)) But now I am no longer restricting each iteranation to 'co_code1'-hypothetically if one co_code1 is followed by another with incremental 'fyear1' difference as 1, growth will be evaluated. Is there a better and more elegant way of doing it? Thanks and regards, Brijesh
On Thu, Dec 15, 2016 at 5:02 PM, Rui Barradas <ruipbarradas at sapo.pt> wrote:
Hello, That is a very common mistake. if() accepts only one TRUE/FALSE, for a vectorized version you need ?ifelse. Something like the following (untested). growth <- ifelse(diff(fyear1)==1, (exp(diff(log(df1$sales1)))-1)*100, NA) Hope this helps, Rui Barradas Em 15-12-2016 03:40, Brijesh Mishra escreveu:
Hi,
I am trying to calculate growth rate (say, sales, though it is to be
computed for many variables) in a panel data set. Problem is that I
have missing data for many firms for many years. To put it simply, I
have created this short dataframe (original df id much bigger)
df1<-data.frame(co_code1=rep(c(1100, 1200, 1300), each=7),
fyear1=rep(1990:1996, 3), sales1=rep(seq(1000,1600, by=100),3))
# this gives me
co_code1 fyear1 sales1
1 1100 1990 1000
2 1100 1991 1100
3 1100 1992 1200
4 1100 1993 1300
5 1100 1994 1400
6 1100 1995 1500
7 1100 1996 1600
8 1200 1990 1000
9 1200 1991 1100
10 1200 1992 1200
11 1200 1993 1300
12 1200 1994 1400
13 1200 1995 1500
14 1200 1996 1600
15 1300 1990 1000
16 1300 1991 1100
17 1300 1992 1200
18 1300 1993 1300
19 1300 1994 1400
20 1300 1995 1500
21 1300 1996 1600
# I am now removing a couple of rows
df1<-df1[-c(5, 8), ]
# the result is
co_code1 fyear1 sales1
1 1100 1990 1000
2 1100 1991 1100
3 1100 1992 1200
4 1100 1993 1300
6 1100 1995 1500
7 1100 1996 1600
9 1200 1991 1100
10 1200 1992 1200
11 1200 1993 1300
12 1200 1994 1400
13 1200 1995 1500
14 1200 1996 1600
15 1300 1990 1000
16 1300 1991 1100
17 1300 1992 1200
18 1300 1993 1300
19 1300 1994 1400
20 1300 1995 1500
21 1300 1996 1600
# so 1994 for co_code1 1100 and 1990 for co_code1 1200 have been
removed. If I try,
d<-ddply(df1,"co_code1",transform,
growth=c(NA,exp(diff(log(sales1)))-1)*100)
# this apparently gives wrong results for the year 1995 (as shown
below) as growth rates are computed considering yearly increment.
co_code1 fyear1 sales1 growth
1 1100 1990 1000 NA
2 1100 1991 1100 10.000000
3 1100 1992 1200 9.090909
4 1100 1993 1300 8.333333
5 1100 1995 1500 15.384615
6 1100 1996 1600 6.666667
7 1200 1991 1100 NA
8 1200 1992 1200 9.090909
9 1200 1993 1300 8.333333
10 1200 1994 1400 7.692308
11 1200 1995 1500 7.142857
12 1200 1996 1600 6.666667
13 1300 1990 1000 NA
14 1300 1991 1100 10.000000
15 1300 1992 1200 9.090909
16 1300 1993 1300 8.333333
17 1300 1994 1400 7.692308
18 1300 1995 1500 7.142857
19 1300 1996 1600 6.666667
# I thought of using the formula only when the increment of fyear1 is
only 1 while in a co_code1, by using this formula
d<-ddply(df1,
"co_code1",
transform,
if(diff(fyear1)==1){
growth=(exp(diff(log(df1$sales1)))-1)*100
} else{
growth=NA
})
But, this doesn't work. I am getting the following error.
In if (diff(fyear1) == 1) { :
the condition has length > 1 and only the first element will be used
(repeated a few times).
# I have searched for a solution, but somehow couldn't get one. Hope
that some kind soul will guide me here.
Regards,
Brijesh K Mishra
Indian Institute of Management, Indore
India
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