Lubdridate: subset based on hour and minute
Hi Joe: See below.
On Jan 2, 2017, at 12:01 PM, Joe Ceradini <joeceradini at gmail.com> wrote:
Hi folks,
I must be missing something obvious/painfully simple here....
How do I subset a time vector based on hours AND minutes? So, in this
example, I want all time greater than 10:00, i.e., 10:30 and 11:00.
I'm working with lubridate which separates the hours and minutes into
separate slots.
require(lubridate)
test <- hm(c("9:30", "10:00", "10:30", "11:00"))
test
[1] "9H 30M 0S" "10H 0M 0S" "10H 30M 0S" "11H 0M 0S"
This gets 11 but not 1030
test[test at hour > 10]
[1] "11H 0M 0S"
This gets 1030 but not 11
test[test at hour > 9 & test at minute > 0]
[1] "10H 30M 0S"
test[test at hour > 9] [1] "10H 0M 0S" "10H 30M 0S" "11H 0M 0S" You are using a logical "and" in your test - so the condition "test at minute > 0" isn't met for 11:00 and therefore it doesn't show up. as both conditions must be met You could also do:
test[test at hour >= 10]
[1] "10H 0M 0S" "10H 30M 0S" "11H 0M 0S" -HTH, Roy
Thanks and happy new year! Joe
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