How to use tapply with more than one variables grouped
On Oct 23, 2012, at 1:25 PM, noobmin wrote:
AL AR CA NY Doug 250 250 250 NA Jennifer 20 340 300 100 Michele 250 500 250 60 Obama 15 45 520 600 My English is not very good, I'll try again. I want to list ALL states in the country where Obama had greater contribution. The table above shows the total contribution received by each candidate in a given state. To AL state obama not received more than Doug. For the AR state he received no more than others candidates. For the CA state he received a total of $ 520, which is 520>300>250>=250 and should be selected. In NY also had the largest contribution, $ 600, 600>100>60 and should therefore be selected. I want to make it to the N presidency candidates and M states of the country. The table above is only an example.
Perhaps:
apply(dat, 2, function(x) x["Obama"] == max(x, na.rm=TRUE) )
AL AR CA NY FALSE FALSE TRUE TRUE Or perhaps:
names(dat)[ apply(dat, 2, function(x) x["Obama"] == max(x, na.rm=TRUE) ) ]
[1] "CA" "NY"
Sorry again, for me it was clear. = ( Thanks -- View this message in context: http://r.789695.n4.nabble.com/How-to-use-tapply-with-more-than-one-variables-grouped-tp4646948p4647220.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD Alameda, CA, USA