Extracting File Basename without Extension

Berwin A Turlach wrote:

G'day all,

On Fri, 9 Jan 2009 08:12:18 -0200
"Henrique Dallazuanna" <wwwhsd at gmail.com> wrote:

Try this also:

substr(basename(myfile), 1, nchar(basename(myfile)) - 4)

Or, in case that the extension has more than three letters or "myfile"
is a vector of names:

R> myfile <- "path1/path2/myoutput.txt"
R> sapply(strsplit(basename(myfile),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
[1] "myoutput"
R> myfile2 <- c(myfile, "path2/path3/myoutput.temp")
R> sapply(strsplit(basename(myfile2),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
[1] "myoutput" "myoutput"
R> myfile3 <- c(myfile2, "path4/path5/my.out.put.xls")
R> sapply(strsplit(basename(myfile3),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
[1] "myoutput"   "myoutput"   "my.out.put"

or have sub do the job for you:

filenames.ext = c("foo.bar", basename("foo/bar/hello.dolly"))
(filenames.noext = sub("[.][^.]*$", "", filenames.ext, perl=TRUE))