obtaining null components of a list
Try this:
x <- list(NULL, 1:10, 25, NULL, "more") x
[[1]] NULL [[2]] [1] 1 2 3 4 5 6 7 8 9 10 [[3]] [1] 25 [[4]] NULL [[5]] [1] "more"
which(sapply(x, is.null))
[1] 1 4
On Wed, Jan 21, 2009 at 7:42 AM, diego Diego <dhabbyc at gmail.com> wrote:
Hello everybody!
I have a list of length 5000 whose components are (mostly) "ts" objects,
but some these components are intentionally left empty, ie, they are "NULL"
components of the list. My question is how can I get the position of these
null components in a effective way (I'm trying to avoid a for-if rutine).
Thanks!!!
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