screen if a value is within range

15 < a & a < 20

Wrap it in a function if you like:

in_interval <- function(x, interval){
  stopifnot(length(interval) == 2L)
  interval[1] < x & x < interval[2]
}

in_interval(a, c(15, 20))

Could just use the findInterval function:

findInterval(x, c(15,20) ) == 1

findInterval returns a numeric vector indicating which bin(s) the  
argument vector element(s) fall(s) into. Items below the lower bound  
get a zero which means if the result is used as an index the there  
will be no item chosen for that value. Items above the maximal  
boundary get a value of n+1 where n is the number of bins. (Very  
useful function.)
David.
> Cheers,
> Michael
>
> On Sat, Dec 1, 2012 at 4:50 PM, Andras Farkas <motyocska at yahoo.com>  
> wrote:
>>
>> could you please give me some pointers on how I could make R screen  
>> for a value if it falls within a certain range?
>> I looked at the subset function, but is not doing it, perhaps  
>> because I only have 1 value to screen?
>>
>> aptreciate the input
>>
>> ex:
>> a <-16.5
>> I would like to screen to see if a is within the range of 15 to 20,  
>> (which it is:-)), and I would like the code to return a value of 1  
>> if a is within the specified range or 0 if it is not.
>>
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

David Winsemius, MD
Alameda, CA, USA

screen if a value is within range

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