setting up a matrix structure
Try this: n <- 3; m <- 2 # test values kronecker(diag(n), matrix(1, 1, m))
On 12/23/05, Erin Hodgess <hodgess at gator.dt.uh.edu> wrote:
Dear R People: I have an n x (nm) matrix. In the first row, there will be n ones, followed by n(m-1) zeros. In the second row, there will be n zeros, n ones, and the rest zeros. In the third row, 2n zeros, n 1 and the rest zeros. . . . In the nth row, n(m-1) zeros and n ones. My question: how can I do this elegantly and efficiently, please? A loop will work just fine, but there must be a better way, please. Thanks for any help! R Version 2.2.0, Windows. Sincerely, Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: hodgess at gator.uhd.edu
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