Help plz to fix it
This looks like homework to me. Here's a hint, though: p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10) This is not how you create a vector in R. for (i in 1 to x) This is not how you create a for loop in R. Sarah
On Mon, Oct 22, 2012 at 2:41 PM, Rlotus <yerlan_ at hotmail.com> wrote:
I have an array of probabilities....it is p. So if user types x=1 then
probability is p1=1/10.
If user types x=2 it means that p2= p1+p2
if user types x=3 it means that p3=p1+p2+p3....and so on.
So i created a code..... but it doesnt work properly. Help me plz to fix it)
Thank u in advance.
psidp=function(x){
p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
i==0;
if (x!=0){
for (i in 1 to x)
{p[i]=p[i]+p[i-1]
p[i]
}
}
Sarah Goslee http://www.functionaldiversity.org