a weird "cut" question
You picked a data set and ask whether the function parameters can fix the partition. Perhaps you should consider a different data set: rep(47677,9). I think you cannot "fix" the partition without considering the data also. Given that, you may be able to go back and manually identify a partition that works with a particular data set (e.g. use quantiles), but you may be asking too much to automate that for all data sets.
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Erin Hodgess <erinm.hodgess at gmail.com> wrote:
Dear R People: I have the following data:
ail.df[,1]
[1] 47677 47602 47678 47905 47909 47906 47605 47673 47607
cut(ail.df[,1],breaks=3)
[1] (4.76e+04,4.77e+04] (4.76e+04,4.77e+04] (4.76e+04,4.77e+04] [4] (4.78e+04,4.79e+04] (4.78e+04,4.79e+04] (4.78e+04,4.79e+04] [7] (4.76e+04,4.77e+04] (4.76e+04,4.77e+04] (4.76e+04,4.77e+04] Levels: (4.76e+04,4.77e+04] (4.77e+04,4.78e+04] (4.78e+04,4.79e+04]
so I have cut ail.df[,1] into 3 levels. However, the second level never appears in the data set. Is there a way to set cut such that every level appears, please? thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston - Downtown mailto: erinm.hodgess at gmail.com
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