Thank you. I'll try this. --- Kai
On Friday, September 16, 2022 at 11:01:33 AM PDT, Rui Barradas <ruipbarradas at sapo.pt> wrote:
Hello,
Something like the following might work.
filenames <- list.files(pattern = "^file\\d+\\.txt$")
destnames <- sapply(filenames, scan, what = character(), sep = "\n", n =
1L, strip.white = TRUE)
if(length(filenames) == length(destnames))
? file.rename(filenames, destnames)
else message("something went wrong")
But I would make copies of 2 or 3 files first and test with, say,
filenames[1:2] and destnames[1:2]
Hope this helps,
Rui Barradas
?s 18:51 de 16/09/2022, Kai Yang escreveu:
? Hello,Here is the example:
? ??file name? ? first row??file1.txt? ? ?abc.txt??file2.txt? ? ?bed.txt??file3.txt? ? ?gogo.txt??.?.?file1243.txt? ? last.txt
I want to use loop because I need to read the first row information for first file, and then rename the file, then go to next file. I'm not sure if this is right way to approach my goal. Any suggestion will be appreciated.?Thanks,?Kai? ? On Friday, September 16, 2022 at 10:38:32 AM PDT, Rui Barradas <ruipbarradas at sapo.pt> wrote:
? Hello,
Please post the first row of 2 or 3 files and the expected result.
You can rename files with ?file.rename. This function is vectorized its
on arguments so you do not need a loop, only the source and destination
filenames. Both vectors should have the same length, if not strange
things will occur including data loss.
Hope this helps,
Rui Barradas
?s 18:26 de 16/09/2022, Kai Yang via R-help escreveu:
Hello,I have a lot of files with not meaningful name, such as:? file1.txt, file2.txt ...... I need to rename them using the information from the first row of the files. Now I can get the information from the first row of each file. Now, I need know how to rename them in R (using loop?).?Thank you for your helpKai
? ??? [[alternative HTML version deleted]]