random effects model

HI AK

Thanks a lot? for explaining that. 

1. With the chi sq. ( in order to find out if the diffce is significant between groups) do I have create a separate excel file and make a dataframe.How do I go about it?

I have resent a mail to Jun Yan at a difft email ad( first add.didn't work, mail not delivered).

2. With my previous query ( reg. Obese/Overweight/ Normal at age 14 Vs change of blood pressure status at 21), even though I had compromised without the age-specific regression, but I am still keen to explore why the age-specific regression didn't work despite it looking okay. I have given below the syntax. If you get time, could you kindly look at it and see if it could work by any chance? Apologies for persisting with this query.


BP.stack3 <-
reshape(Copy.of.BP_2,idvar="CODEA",timevar="time",sep="_",varying=list(c("Obese14","Obese21"),c("Overweight14","Overweight21")),v.names=c("Obese","Overweight"),times=factor(c(1,2)),direction="long
BP.stack3
head(BP.stack3)
tail(BP.stack3)

?names(BP.stack3)[c(2,3,4,5,6,7)] <-
c("Sex","MaternalAge","Education","Birthplace","AggScore","IntScore") 

BP.stack3 <-
transform(BP.stack3,CODEA=factor(CODEA),Sex=factor(Sex,labels=c("Male","Female")),MaternalAge=factor(MaternalAge,labels=c("39years
or less","40-49 years","50 years or
older")),Education=factor(Education,labels=c("Primary/special","Started
secondary","Completed grade10", "Completed grade12",
"College","University")),Birthplace=factor(Birthplace,labels=c("Australia","Other
English-speaking","Other")))

table(BP.stack3$Sex)??
BP.stack3$Sex <-
factor(BP.stack3$Sex,levels=levels(BP.stack3$Sex)[c(2,1)]) 

levels(BP.stack3$Sex)
BP.sub3a <-? subset(BP.stack3,subset=!(is.na(Sex)| is.na(Education)|is.na(Birthplace)|is.na(Education)|is.na(hibp14)| is.na(hibp21)))???
summary(BP.sub3a)
BP.sub5a <- BP.sub3a[order(BP.sub5a$CODEA),]?
?BPsub3$Categ[BPsub6$Overweight==1&BPsub3$time==1&BPsub3$Obese==0]
<- "Overweight14"
BPsub3$Categ[BPsub6$Overweight==1&BPsub3$time==2&BPsub3$Obese==0]
<- "Overweight21"
BPsub3$Categ[BPsub3$Obese==1&BPsub3$time==1&BPsub3$Overweight==0|BPsub3$Obese==1&BPsub3$time==1&BPsub3$Overweight==1
] <- "Obese14"
BPsub3$Categ[BPsub3$Obese==0&BPsub3$time==1&BPsub3 BPsub3$Categ[BPsub6$Overweight==1&BPsub3$time==1&BPsub3$Obese==0]
<- "Overweight14"$Overweight==0]
<- "Normal14"
BPsub3$Categ[BPsub3$Obese==0&BPsub3$time==2&BPsub3$Overweight==0]
<- "Normal21"
BPsub3$Categ[BPsub3$Obese==1&BPsub3$time==2&BPsub3$Overweight==0|BPsub3$Obese==1&BPsub3$time==2&BPsub3$Overweight==1]
<- "Obese21"



BPsub3$Categ <- factor(BPsub3$Categ)
BPsub3$time <- factor(BPsub3$time)
summary(BPsub3$Categ)
BPsub7 <- subset(BPsub6,subset=!(is.na(Categ)))
BPsub7$time <-
recode(BPsub7$time,"1=14;2=21")
BPsub7$hibp14 <- factor(BPsub7$hibp14)
levels(BPsub7$hibp14)
levels(BPsub7$Categ)
names(BPsub7)
head(BPsub7)??? ### this was looking quite okay.

tail(BPsub7)
str(BPsub7)

library(gee)

BP.gee <- geese(hibp14~ time*Categ,
data=BPsub7,id=CODEA,family=binomial,
corstr="exchangeable",na.action=na.omit)

Thanks again.



On Sun, Jan 13, 2013 at 1:22 PM, arun <smartpink111 at yahoo.com> wrote:

HI,
>????
>table(BP_2b$Sex) #original dataset
>#?? 1??? 2
>#3232 3028
>?nrow(BP_2b)
>#[1] 6898
>?nrow(BP_2bSexNoMV)
>#[1] 6260
>?6898-6260
>#[1] 638 #these rows were removed from the BP_2b to create BP_2bSexNoMV
>BP_2bSexMale<-BP_2bSexNoMV[BP_2bSexNoMV$Sex=="Male",]
>?nrow(BP_2bSexMale)
>#[1] 3232
>?nrow(BP_2bSexMale[!complete.cases(BP_2bSexMale),]) #Missing rows with Male
>#[1] 2407
>?nrow(BP_2bSexMale[complete.cases(BP_2bSexMale),]) #Non missing rows with Male
>#[1] 825
>
>
>You did the chisquare test on the new dataset with 6260 rows, right.
>I removed those 638 rows because these doesn't belong to either male or female, but you want the % of missing value per male or female.? So, I thought this will bias the results.? If you want to include the missing values, you could do it, but I don't know where you would put that missing values as it cannot be classified as belonging specifically to males or females.? I hope you understand it.
>
>Sometimes, the maintainer's respond a bit slow.? You have to sent an email reminding him again.
>
>Regarding the vmv package, you could email Waqas Ahmed Malik (malik at math.uni-augsburg.de) regarding options for changing the title and the the font etc.
>You could also use this link (http://www.r-bloggers.com/visualizing-missing-data-2/ ) to plot missing value (?plot.missing()).? I never used that package, but you could try.? Looks like it gives more information.
>
>A.K.
>
>
>
>
>
>
>
>
>________________________________
>From: Usha Gurunathan <usha.nathan at gmail.com>
>To: arun <smartpink111 at yahoo.com>
>Sent: Saturday, January 12, 2013 9:05 PM
>
>Subject: Re: [R] random effects model
>
>
>Hi A.K
>
>So it is number of females missing/total female participants enrolled: 72.65%
>Number of females missing/total (of males+ females) ?participants enrolled : 35.14%
>
>The total no. with the master data: Males: 3232, females: 3028 ( I got this before removing any missing values)
>
>with table(Copy.of.BP_2$ Sex) ?## BP
>
>
>If I were to write a table ( ?and do a chi sq. later),?
>
>as Gender ? ? ? ? ? ?Study ? ? ? ? ? ? ? ? ? ?Non study/missing ? ? Total
>? ? ??Male ? ? ? ? ? ? ?825 (25.53%)? ? ? ? ? ? ?2407 (74.47%) ? ? ? 3232 (100%)
>? ??Female ? ? ? ? ? 828 (27.35%) ? ? ? ? ? ? 2200 (72.65%) ? ? ? 3028 ( 100%)
>? ? ?Total ? ? ? ? ? ? ?1653 ? ? ? ? ? ? ? ? ? ? ? ? ?4607 ? ? ? ? ? ? ? ? ? ? ?6260 ? ?
>
>
>The problem is when I did?
>>colSums(is.na(Copy.of.BP_2), the sex category showed N=638.
>
>I cannot understand the discrepancy.Also, when you have mentioned to remove NA, is that not a missing value that needs to be included in the total number missing. I am a bit confused. Can you help?
>
>## I tried sending email to gee pack maintainer at the ID with R site, mail didn't go through??
>
>Many thanks
>
>
>
>
>
>
>On Sun, Jan 13, 2013 at 9:17 AM, arun <smartpink111 at yahoo.com> wrote:
>
>Hi,
>>Yes, you are right. ?72.655222% was those missing among females. ?35.14377% of values in females are missing from among the whole dataset (combined total of Males+Females data after removing the NAs from the variable "Sex").?
>>
>>A.K.
>>
>>
>>
>>________________________________
>>From: Usha Gurunathan <usha.nathan at gmail.com>
>>To: arun <smartpink111 at yahoo.com>
>>Cc: R help <r-help at r-project.org>
>>Sent: Saturday, January 12, 2013 5:59 PM
>>
>>Subject: Re: [R] random effects model
>>
>>
>>
>>Hi AK
>>That works. I was trying to get? similar results from any other package. Being a beginner, I was not sure how to modify the syntax to get my output.
>>
>>lapply(split(BP_2bSexNoMV,BP_
>>2bSexNoMV$Sex),function(x) (nrow(x[!complete.cases(x[,-2]),])/nrow(x))*100) #gives the percentage of rows of missing #values from the overall rows for Males and Females
>>#$Female
>>#[1] 72.65522
>>#
>>#$Male
>>#[1] 74.47401
>>
>>#iF you want the percentage from the total number rows in Males and Females (without NA's in the the Sex column)
>>?lapply(split(BP_2bSexNoMV,BP_2bSexNoMV$Sex),function(x) (nrow(x[!complete.cases(x[,-2]),])/nrow(BP_2bSexNoMV))*100)
>>#$Female
>>#[1] 35.14377
>>#
>>#$Male
>>#[1] 38.45048
>>
>>How do I interpret the above 2 difft results? 72.66% of values were missing among female participants?? Can you pl. clarify.
>>
>>Many thanks.
>>
>>
>>On Sun, Jan 13, 2013 at 3:28 AM, arun <smartpink111 at yahoo.com> wrote:
>>
>>lapply(split(BP_2bSexNoMV,BP_2bSexNoMV$Sex),function(x) (nrow(x[!complete.cases(x[,-2]),])/nrow(x))*100) #gives the percentage of rows of missing #values from the overall rows for Males and Females
>>>#$Female
>>>#[1] 72.65522
>>>#
>>>#$Male
>>>#[1] 74.47401
>>>
>>>#iF you want the percentage from the total number rows in Males and Females (without NA's in the the Sex column)
>>>?lapply(split(BP_2bSexNoMV,BP_2bSexNoMV$Sex),function(x) (nrow(x[!complete.cases(x[,-2]),])/nrow(BP_2bSexNoMV))*100)
>>>#$Female
>>>#[1] 35.14377
>>>#
>>>#$Male
>>>#[1] 38.45048
>>
>??????