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How to handle large numbers?

Feng

checkout the Brobdingnag package:


 > library(Brobdingnag)
 > exp(1000)/(exp(1007)+5)
[1] NaN

 > as.numeric(exp(as.brob(1000))/(exp(as.brob(1007))+5))
[1] 0.000911882
 >
Feng Li wrote: