Data Extraction

Hi,

is.na<http://is.na/>( X1 | X2 | X3 | X4 | X5)
isn't a valid construct.

You'd need
!(is.na<http://is.na>(X1) | is.na<http://is.na>(X2) etc )

Or more elegantly
df1[apply(df1, 1, function(x)all(!is.na<http://is.na>(x))), ]

Sarah

On Thursday, November 22, 2012, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hello,

I would appreciate if someone could help me resolve the following:

1. df1[!is.na<http://is.na>( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work

2. Is these message harmful?  The following object(s) are masked from 'df1 (position 3)':
    X1, X2, X3, X4, X5

Thanks,

Pradip Muhuri


#Reproducible Example
set.seed(5)
df1<-data.frame(matrix(sample(c(1:10,NA),100,replace=TRUE),ncol=5))
attach (df1)
#delete rows if any of them NA for X1
df1[!is.na<http://is.na>( X1),][,1:5] # This works

#delete rows if any of them NA for X1, X2, X3, X4 or X5
df1[!is.na<http://is.na>( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work

______________________________________________
R-help at r-project.org<javascript:;> mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


--
Sarah Goslee
http://www.stringpage.com
http://www.sarahgoslee.com
http://www.functionaldiversity.org