From: Rich FitzJohn <rich.fitzjohn at gmail.com>
Reply-To: Rich FitzJohn <rich.fitzjohn at gmail.com>
To: "Francisco J. Zagmutt" <gerifalte28 at hotmail.com>
CC: R-help at stat.math.ethz.ch
Subject: Re: [R] i param in "for" loop does not takes zeros?
Date: Thu, 14 Apr 2005 09:36:21 +1200
The for loop is not ignoring the zero at all, but the assignment is,
since R indexes starting at 1, not zero.
sim <- c()
sim[0] <- 1
sim
numeric(0)
To run this loop this way, you need to add one to the index:
for ( i in 0:5 )
sim[i+1] <- dbinom(i, 5, p)
However, you'd be better off passing your vector of values directly to
dbinom():
[1] 0.32768 0.40960 0.20480 0.05120 0.00640 0.00032
all(dbinom(0:5, 5, p) == sim)
[1] TRUE
Cheers,
Rich
On 4/14/05, Francisco J. Zagmutt <gerifalte28 at hotmail.com> wrote:
Hi all
Is there any reason why the parameter i in a "for" loop ignores a value
zero? For example
sim=c()
p=.2
for(i in 0:5)
{sim[i]=dbinom(i,5,p)
}
sim
[1] 0.40960 0.20480 0.05120 0.00640 0.00032
In this example the quantile i= 0 was ignored since
dbinom(0,5,p)
[1] 0.32768
The same behaviour occurs if I use a while loop to perform the same
calculation:
sim=c()
p=.2
i=0
while(i <6)
{sim[i]=dbinom(i,5,p)
i=i+1
}
sim
[1] 0.40960 0.20480 0.05120 0.00640 0.00032
How can I perform a loop passing a zero value parameter? I know I can
an if statement for i<=0 but I was wondering why the loop is ignoring
zero value.
Many thanks!
Francisco