From replicate to accesing sublists
Thanks.The code you gave me at the end works correctly.. I was wondering if there is more efficient way to access each element withouth this classic for loop. RegardsAlex
On Wednesday, April 1, 2015 5:54 PM, David Winsemius <dwinsemius at comcast.net> wrote:
On Apr 1, 2015, at 3:34 AM, Alaios via R-help wrote:
Dear all,I have a R structure that was created with replicate.The data sets looks to be a matrix with each cell being a list. str(error_suburban_0[,1],max.level=1) List of 4 $ vaR? ? ? :List of 20 ? ..- attr(*, "class")= chr "variogram" $ Shadowing:List of 2 ? ..- attr(*, "class")= chr "geodata" $ FIT? ? ? :List of 1 $ propmodel:List of 12 ? ..- attr(*, "class")= chr "lm" The error_suburban is a matrix that each field so error_suburban_0[,1], error_suburban_0[,2], error_suburban_0[,3], error_suburban_0[,4],... and so on,? contains the four sublists $ vaR? ? ? :List of 20 ? ..- attr(*, "class")= chr "variogram" $ Shadowing:List of 2 ? ..- attr(*, "class")= chr "geodata" $ FIT? ? ? :List of 1 $ propmodel:List of 12 ? ..- attr(*, "class")= chr "lm" I would like to pick for each of these matrix elements to collect only the $Shadowing sublist error_suburban_0[,1], error_suburban_0[,2], error_suburban_0[,3], error_suburban_0[,4]... and so on Right now I am implementing this by a for loop that access each matrix element sequentially.
It would have been better to show the results of dim() or dput(). Matrix objects (which are capable of holding lists) should be accessible with either a single or double argument to "[". This should deliver contents: for (i in 1:4)? print(? error_suburban_0[i]$Shadowing ) If the matrix has 4 or more rows, then that would be accessing only from the first column. If fewer than 4 rows, you would be wrapping around to later columns. -- David.
Can you please advice me if there is a better approach to do that in R? Regards Alex ? ??? [[alternative HTML version deleted]]
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David Winsemius Alameda, CA, USA [[alternative HTML version deleted]]