na.action in stats::factanal() must be using formula interface and dataframe input to specify na.action?
On 06.02.2012 18:42, Timothy Bates wrote:
hi, Does factanal() force the user to use the formula interface if they wish to specify an na.action?
Yes, as the help page says: "na.action: The ?na.action? to be used if ?x? is used as a formula." Uwe Ligges
v1<- c(1,1,1,1,1,1,1,1,NA,1,3,3,3,3,3,4,5,6) v2<- c(1,2,1,1,1,1,2,1,2,1,3,NA,3,3,3,4,6,5) v3<- c(3,3,3,3,3,1,1,1,1,1,1,1,1,1,1,5,4,6) v4<- c(3,3,4,NA,3,1,1,2,1,1,1,1,2,NA,1,5,6,4) v5<- c(1,1,1,1,1,3,3,3,3,3,1,1,1,1,1,6,4,5) v6<- c(1,1,1,2,1,3,3,3,4,3,1,1,1,2,1,6,5,4) m1<- data.frame(cbind(v1,v2,v3,v4,v5,v6)) factOut = factanal(m1, factors = 1,scores = "Bartlett", na.action="na.exclude") factOut = factanal(~v1+v2+v3+v4+v5+v6, data=m1, factors = 1,scores = "Bartlett", na.action="na.exclude")
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