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Help with speed (replacing the loop?)

Hi,

On Wed, Jan 11, 2012 at 10:50 AM, Dimitri Liakhovitski
<dimitri.liakhovitski at gmail.com> wrote:
Fair enough ... how about just using `match`, then, ie:

R> aa <- x$a * y$a[match(x$group, y$group)]

Should do the trick, no?

-steve