making a dataframe out of lapply() result
You could try:
s <- lapply(tester.L, function(x) x <- x[1,] )
do.call("rbind", s)
-roger
_______________________________
UCLA Department of Statistics
http://www.stat.ucla.edu/~rpeng
On Tue, 15 Apr 2003, Remko Duursma wrote:
Dear R-helpers,
i have a question on how to vectorize this problem:
i have a dataframe:
tester <- data.frame(groups=c("A","A","B","B","C","C"), one=c(1,1,2,2,3,3), two=c(6,6,7,7,8,8))
# i split it into a list
tester.L <- split(tester, tester$groups)
# And want to keep only the first item in each:
lapply(tester.L, function(x) x <- x[1,] )
How do i make a dataframe out of the last result, which looks like
"tester", without looping? (i can use rbind in a for loop, but is
rather slow)
thanks for your help,
Remko Duursma
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