HI,
May be this is what you wanted.
?res1<-aggregate(dattrial2$a,list(dattrial2$Week,dattrial2$AnimalID),function(x) sum(is.na(x)))
split(res1,res1$Group.2)
#$Bert
#? Group.1 Group.2 x
#1?????? 3??? Bert 1
#2?????? 4??? Bert 1
#$Ernie
?# Group.1 Group.2 x
#3?????? 3?? Ernie 1
#4?????? 4?? Ernie 0
A.K.
----- Original Message -----
From: Tagmarie <Ramgad82 at gmx.net>
To: r-help at r-project.org
Cc:
Sent: Monday, September 17, 2012 9:07 AM
Subject: Re: [R] count NAs per week
Thank you Michael, that worked perfectly!
Now I wonder, if it is possible to break my data further apart and put it
together again.
Assume I include a column for an ID in the data frame like this:
dattrial2<-data.frame(a=c(1,NA,NA,NA,2,3), Week=c(3,3,3,4,4,4),
AnimalID=c("Ernie","Bert", "Ernie", "Bert", "Bert", "Ernie"))
Is it possible to get two different lists in the output, one for Ernie and
one for Bert? Or do I have to do it seperately for each animal?
Thank you again! I learn a lot by doing and by people helping me. Thank you
for the hint with the paper.
--
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